The Redskins have clinched last place in NFC East

The Redskins will finish in last place in the NFC East even if they win their final two games to go 5-11 (Jonathan Newton/The Washington Post)

The Redskins will finish in last place in the NFC East even if they win their final two games to go 5-11 (Jonathan Newton/The Washington Post)

The Washington Redskins have clinched last place in the NFC East.

The Redskins, at 3-11, are two games behind the third-place New York Giants, who are 5-9, with two games to play. The two teams play each other in the season finale.

But even if the Redskins win their final two games and the Giants lose their final two games so that each team finishes 5-11, the Giants would finish ahead of the Redskins on tie-breakers.

It would require the fourth tie-breaker, conference records, because the two teams would have split their head-to-head meetings; each would have a division record of 2-4; and each would be 4-8 against common opponents under that scenario. The Giants, at worst, will be 4-8 against NFC opponents while the Redskins, at best, will be 3-9.

Have a Redskins question? E-mail Mike Jones at mike.jones@washpost.com with the subject line “Mailbag question” for him to answer it in The Mailbag on Tuesdays.

What’s ahead:

●  The Redskins practice at 11:50 on Thursday, with coordinators Kyle Shanahan and Jim Haslett and head coach Mike Shanahan expected to speak with reporters afterward.

More on the Redskins and NFL:

Reid: If Shanahan returned, who’d want to come along?

Griffin tries to heed Fletcher’s advice to ‘exhale’

Cousins aims to build off success vs. Falcons

D.C. Sports BogBrown says Shanahan has acted professionally | More

Fletcher ’99 percent certain’ he’ll retire | Wants Shanahan back

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